- /*
- * @(#)Comparable.java 1.13 00/02/02
- *
- * Copyright 1997-2000 Sun Microsystems, Inc. All Rights Reserved.
- *
- * This software is the proprietary information of Sun Microsystems, Inc.
- * Use is subject to license terms.
- *
- */
-
- package java.lang;
-
- /**
- * This interface imposes a total ordering on the objects of each class that
- * implements it. This ordering is referred to as the class's <i>natural
- * ordering</i>, and the class's <tt>compareTo</tt> method is referred to as
- * its <i>natural comparison method</i>.<p>
- *
- * Lists (and arrays) of objects that implement this interface can be sorted
- * automatically by <tt>Collections.sort</tt> (and <tt>Arrays.sort</tt>).
- * Objects that implement this interface can be used as keys in a sorted map
- * or elements in a sorted set, without the need to specify a comparator.<p>
- *
- * A class's natural ordering is said to be <i>consistent with equals</i> if
- * and only if <tt>(e1.compareTo((Object)e2)==0)</tt> has the same boolean
- * value as <tt>e1.equals((Object)e2)</tt> for every <tt>e1</tt> and
- * <tt>e2</tt> of class <tt>C</tt>.<p>
- *
- * It is strongly recommended (though not required) that natural orderings be
- * consistent with equals. This is so because sorted sets (and sorted maps)
- * without explicit comparators behave "strangely" when they are used with
- * elements (or keys) whose natural ordering is inconsistent with equals. In
- * particular, such a sorted set (or sorted map) violates the general contract
- * for set (or map), which is defined in terms of the <tt>equals</tt>
- * operation.<p>
- *
- * For example, if one adds two keys <tt>a</tt> and <tt>b</tt> such that
- * <tt>(a.equals((Object)b) && a.compareTo((Object)b) != 0)</tt> to a sorted
- * set that does not use an explicit comparator, the second <tt>add</tt>
- * operation returns false (and the size of the sorted set does not increase)
- * because <tt>a</tt> and <tt>b</tt> are equivalent from the sorted set's
- * perspective.<p>
- *
- * Virtually all Java core classes that implement comparable have natural
- * orderings that are consistent with equals. One exception is
- * <tt>java.math.BigDecimal</tt>, whose natural ordering equates
- * <tt>BigDecimals</tt> with equal values and different precisions (such as
- * 4.0 and 4.00).<p>
- *
- * For the mathematically inclined, the <i>relation</i> that defines
- * the natural ordering on a given class C is:<pre>
- * {(x, y) such that x.compareTo((Object)y) <= 0}.
- * </pre> The <i>quotient</i> for this total order is: <pre>
- * {(x, y) such that x.compareTo((Object)y) == 0}.
- * </pre>
- *
- * It follows immediately from the contract for <tt>compareTo</tt> that the
- * quotient is an <i>equivalence relation</i> on <tt>C</tt>, and that the
- * natural ordering is a <i>total order</i> on <tt>C</tt>. When we say that a
- * class's natural ordering is <i>consistent with equals</i>, we mean that the
- * quotient for the natural ordering is the equivalence relation defined by
- * the class's <tt>equals(Object)</tt> method:<pre>
- * {(x, y) such that x.equals((Object)y)}.
- * </pre>
- *
- * @author Josh Bloch
- * @version 1.13, 02/02/00
- * @see java.util.Comparator
- * @see java.util.Collections#sort(java.util.List)
- * @see java.util.Arrays#sort(Object[])
- * @see java.util.SortedSet
- * @see java.util.SortedMap
- * @see java.util.TreeSet
- * @see java.util.TreeMap
- * @since 1.2
- */
-
- public interface Comparable {
- /**
- * Compares this object with the specified object for order. Returns a
- * negative integer, zero, or a positive integer as this object is less
- * than, equal to, or greater than the specified object.<p>
- *
- * The implementor must ensure <tt>sgn(x.compareTo(y)) ==
- * -sgn(y.compareTo(x))</tt> for all <tt>x</tt> and <tt>y</tt>. (This
- * implies that <tt>x.compareTo(y)</tt> must throw an exception iff
- * <tt>y.compareTo(x)</tt> throws an exception.)<p>
- *
- * The implementor must also ensure that the relation is transitive:
- * <tt>(x.compareTo(y)>0 && y.compareTo(z)>0)</tt> implies
- * <tt>x.compareTo(z)>0</tt>.<p>
- *
- * Finally, the implementer must ensure that <tt>x.compareTo(y)==0</tt>
- * implies that <tt>sgn(x.compareTo(z)) == sgn(y.compareTo(z))</tt>, for
- * all <tt>z</tt>.<p>
- *
- * It is strongly recommended, but <i>not</i> strictly required that
- * <tt>(x.compareTo(y)==0) == (x.equals(y))</tt>. Generally speaking, any
- * class that implements the <tt>Comparable</tt> interface and violates
- * this condition should clearly indicate this fact. The recommended
- * language is "Note: this class has a natural ordering that is
- * inconsistent with equals."
- *
- * @param o the Object to be compared.
- * @return a negative integer, zero, or a positive integer as this object
- * is less than, equal to, or greater than the specified object.
- *
- * @throws ClassCastException if the specified object's type prevents it
- * from being compared to this Object.
- */
- public int compareTo(Object o);
- }